Hi Emil,
On 13 April 2016 at 20:15, Emil Velikov emil.l.velikov@gmail.com wrote:
Hi Xinliang,
On 11 April 2016 at 09:55, Xinliang Liu xinliang.liu@linaro.org wrote:
+static int kirin_drm_connectors_register(struct drm_device *dev) +{
struct drm_connector *connector;struct drm_connector *failed_connector;int ret;mutex_lock(&dev->mode_config.mutex);drm_for_each_connector(connector, dev) {ret = drm_connector_register(connector);if (ret) {failed_connector = connector;goto err;}}mutex_unlock(&dev->mode_config.mutex);return 0;+err:
drm_for_each_connector(connector, dev) {if (failed_connector == connector)break;drm_connector_unregister(connector);}mutex_unlock(&dev->mode_config.mutex);return ret;+}
Iirc we have new drm_connector_{un,}register_all() helpers.You might want to use it once they are in (i.e. not sure what your base is and if they have landed yet).
I can't find these drm_connector_{un,}register_all() helpers in latest tag v4.6-rc3.
+static struct device_node *kirin_get_remote_node(struct device_node *np) +{
struct device_node *endpoint, *remote;/* get the first endpoint, in our case only one remote node* is connected to display controller.*/endpoint = of_graph_get_next_endpoint(np, NULL);if (!endpoint) {DRM_ERROR("no valid endpoint node\n");return ERR_PTR(-ENODEV);}of_node_put(endpoint);remote = of_graph_get_remote_port_parent(endpoint);if (!remote) {DRM_ERROR("no valid remote node\n");return ERR_PTR(-ENODEV);}of_node_put(remote);if (!of_device_is_available(remote)) {DRM_ERROR("not available for remote node\n");return ERR_PTR(-ENODEV);}This seems like a common pattern in many platform DRM drivers. Yet some tend to differ in subtle ways - I'm leaning that they might be bugs, but one cannot be too sure.
A friendly request: Can you please follow up by adding a helper and removing the duplication thoughout ?
Yes, I will create another patch set for this. I think I need to figure out other drivers requirements. Maybe, I need to add one more parameter for this helper. That's endpoint index to get which endpoint remote node. I will follow up this.
Thanks, -xinliang
Thanks Emil