On 2016-04-25 03:16, Archit Taneja wrote:
Calling the legacy gpio_free on an invalid GPIO (a GPIO numbered -1) results in kernel warnings. This causes a lot of backtraces when we try to unload the drm/msm module.
Call gpio_free only on valid GPIOs.
Signed-off-by: Archit Taneja architt@codeaurora.org
drivers/gpu/drm/msm/hdmi/hdmi_connector.c | 19 ++++++++++++------- 1 file changed, 12 insertions(+), 7 deletions(-)
diff --git a/drivers/gpu/drm/msm/hdmi/hdmi_connector.c b/drivers/gpu/drm/msm/hdmi/hdmi_connector.c index 26129bf..ce86117 100644 --- a/drivers/gpu/drm/msm/hdmi/hdmi_connector.c +++ b/drivers/gpu/drm/msm/hdmi/hdmi_connector.c @@ -112,13 +112,16 @@ static int gpio_config(struct hdmi *hdmi, bool on) for (i = 0; i < HDMI_MAX_NUM_GPIO; i++) { struct hdmi_gpio_data gpio = config->gpios[i];
if (gpio.output) {int value = gpio.value ? 0 : 1;
if (gpio.num != -1) {if (gpio.output) {int value = gpio.value ? 0 : 1;
gpio_set_value_cansleep(gpio.num, value);}
gpio_set_value_cansleep(gpio.num,value);}
gpio_free(gpio.num);
gpio_free(gpio.num);}
Can you do something like:
if (gpio.num == -1) continue;
instead? That would avoid the additional indentation (and increase readability).
Thomas